La X∼bin(5; 0,1)X\sim\mathrm{bin}(5;\,0{,}1)X∼bin(5;0,1). Regn ut P(X≥1)P(X\ge 1)P(X≥1).
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$P(X≥1)=1−P(X=0)=1−0,95=1−0,5905≈0,4095.P(X\ge1)=1-P(X=0)=1-0{,}9^5=1-0{,}5905\approx0{,}4095.P(X≥1)=1−P(X=0)=1−0,95=1−0,5905≈0,4095.$ Komplementtrikset sparer mye regning.
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