Normalfordelingen
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f(x)=1σ2πe−(x−μ)2/(2σ2)\displaystyle f(x)=\frac{1}{\sigma\sqrt{2\pi}}e^{-(x-\mu)^2/(2\sigma^2)}f(x)=σ2π1e−(x−μ)2/(2σ2). 68-95-99.7. Z=(X−μ)/σ∼N(0,1)Z=(X-\mu)/\sigma\sim N(0,1)Z=(X−μ)/σ∼N(0,1).
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