2n>n2^{n}>n2n>n
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Basis: 2>12>12>1. Steg: 2n+1=2⋅2n>2n≥n+12^{n+1}=2\cdot 2^{n}>2n\ge n+12n+1=2⋅2n>2n≥n+1 for n≥1n\ge 1n≥1.
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