Oppgave: Ring m = 1{,}5 kg, R = 0{,}30 m, ω = 25 rad/s, horisontal akse, r = 0{,}10 m. Finn Ω\OmegaΩ .(I=mR2). (I = mR^2).(I=mR2)
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I=mR2=1,5⋅0,302=0,135kg⋅m2I = mR^2 = 1{,}5\cdot 0{,}30^2 = 0{,}135 kg\cdot m^2I=mR2=1,5⋅0,302=0,135kg⋅m2.
L = Iω =0,135⋅25=3,375kg⋅m2/s= 0{,}135\cdot 25 = 3{,}375 kg\cdot m^2/s=0,135⋅25=3,375kg⋅m2/s.
τ = mgr =1,5⋅9,81⋅0,10=1,4715N⋅m= 1{,}5\cdot 9{,}81\cdot 0{,}10 = 1{,}4715 N\cdot m=1,5⋅9,81⋅0,10=1,4715N⋅m.
Ω=\Omega =Ω= τ/L=1,4715/3,375=0,436≈0,44/L = 1{,}4715/3{,}375 = 0{,}436 \approx 0{,}44/L=1,4715/3,375=0,436≈0,44 rad/s.
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