Bruk T2T_2T2 til å estimere e0.1e^{0.1}e0.1.
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ex≈1+x+x22\displaystyle e^x\approx 1+x+\frac{x^2}{2}ex≈1+x+2x2. e0.1≈1+0.1+0.005=1.105e^{0.1}\approx 1+0.1+0.005=1.105e0.1≈1+0.1+0.005=1.105. Eksakt ≈1.10517\approx 1.10517≈1.10517.
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