Beregn ∫0π/2sinxcosx dx\int_0^{\pi/2}\sin x\cos x\,dx∫0π/2sinxcosxdx.
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u=sinxu=\sin xu=sinx: ∫01u du=12\displaystyle \int_0^1 u\,du=\frac12∫01udu=21. Alternativt 12∫sin2x dx\displaystyle \frac12\int\sin2x\,dx21∫sin2xdx.
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