Eksponentielt fordelte ventetider med μ=5\mu = 5μ=5 min, σ=5\sigma = 5σ=5 min. For 64 kunder, finn P(Xˉ<4,5)P(\bar{X} < 4{,}5)P(Xˉ<4,5).
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SE=5/8=0,625SE = 5/8 = 0{,}625SE=5/8=0,625. z=4,5−50,625=−0,8\displaystyle z = \frac{4{,}5-5}{0{,}625} = -0{,}8z=0,6254,5−5=−0,8. P(Z<−0,8)=0,212P(Z < -0{,}8) = 0{,}212P(Z<−0,8)=0,212.
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